CHAPTER
3
The study of fluids can be divided into the study of fluids at rest  fluid statics, and the study of fluids in motion  fluid dynamics. For some purposes, further subdivision into compressible fluids such as gases, and incompressible fluids such as liquids, is necessary. Fluids in the food industry vary considerably in their properties. They include such materials as:

FLUID STATICS A very important property of a fluid at rest is the pressure exerted by that fluid on its surroundings, that is the fluid pressure Pressure is defined as force exerted on an area. Under the influence of gravity, a mass of any material exerts a force on whatever supports it. The magnitude of this force is equal to the mass of the material multiplied by the acceleration due to gravity. The mass of a fluid can be calculated by multiplying its volume by its density, which is defined as its mass per unit volume. Thus the equation can be written:
where F is the force exerted, m is the mass, g the acceleration due to gravity, V the volume and r (the Greek letter rho) the density. The units of force are Newtons, or kg m s^{2.} and of pressure Pascals, one Pascal being one Newton m^{2}, and so one Pascal is also one kg m^{1} s^{2.} For a mass to remain in equilibrium, the force it exerts due to gravity must be resisted by some supporting medium. For a weight resting on a table, the table provides the supporting reaction; for a multistorey building, the upper floors must be supported by the lower ones so that as you descend the building the burden on the floors increases until the foundations support the whole building. In a fluid, the same situation applies. Lower levels of the fluid must provide the support for the fluid that lies above them. The fluid at any point must support the fluid above. Also, since fluids at rest are not able to sustain shearing forces, which are forces tending to move adjacent layers in the fluid relative to one another, it can be shown that the forces at any point in a fluid at rest are equal in all directions. The force per unit area in a fluid is called the fluid pressure. It is exerted equally in all directions. Consider a horizontal plane in a fluid at a depth Z below the surface, as illustrated in Fig. 3.1.
If the density of the fluid is r, then the volume of fluid lying above an area A on the plane is ZA and the weight of this volume of fluid, which creates a force exerted by it on the area A which supports it, is ZrAg. But the total force on the area A must also include any additional force on the surface of the liquid. If the force on the surface is P_{s} per unit area,
where F is the total force exerted on the area A and P_{s} is the pressure above the surface of the fluid (e.g. it might be atmospheric pressure). Further, since total pressure P is the total force per unit area,
In general, we are interested in pressures above or below atmospheric. If referred to zero pressure as datum, the pressure of the atmosphere must be taken into account. Otherwise the atmospheric pressure represents a datum or reference level from which pressures are measured. In these circumstances we can write:
This may be considered as the fundamental equation of fluid pressure. It states that the product of the density of the fluid, acceleration due to gravity and the depth gives the pressure at any depth in a fluid.
To this must be added the pressure at the surface of 70 kPa. Total pressure = 70 + 18.1 = 88.1 kPa. Note in Example 3.1, the pressure depends upon the pressure at the top of the tank added to the pressure due to the depth of the liquid; the fact that the tank is spherical (or any other shape) makes no difference to the pressure at the bottom of the tank. In
the previous paragraph, we established that the pressure at a point in
a liquid of a given density is solely dependent on the density of the
liquid and on the height of the liquid above the point, plus any pressure
which may exist at the surface of the liquid. When the depths of the fluid
are substantial, fluid pressures can be considerable. For example, the pressure on a plate 1 m^{2} lying at a depth of 30 m will be the weight of 1 m^{3} of water multiplied by the depth of 30 m and this will amount to 30 x 1000 x 9.81 = 294.3 kPa. As 1 tonne exerts a force on 1 m^{2} of 1000 x 9.81 = 9810 Pa = 9.81 kPa the pressure on the plate is equal to that of a weight of 294.3 / 9.81 = 30 tonnes of water. Pressures are sometimes quoted as absolute pressures and this means the total pressure including atmospheric pressure. More usually, pressures are given as gauge pressures, which implies the pressure above atmospheric pressure as datum. For example, if the absolute pressure is given as 350 kPa, the gauge pressure is (350  100) = 250 kPa assuming that the atmospheric pressure is 100 kPa. These pressure conversions are illustrated in Fig. 3.2.
Another
commonly used method of expressing pressures is in terms of "head"
of a particular fluid. From eqn. (3.3) it can be seen that there is a
definite relationship between pressure and depth in a fluid of given density.
Thus pressures can be expressed in terms of depths, or heads as they are
usually called, of a given fluid.
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